All the best to all the JNU SSS aspirants...!!!!

[Granpa Simpson]

[kangkan]

Hey..how was the paper?

[VINEET]

bad how was yours

[kangkan]

dnt know..there so much NIA in paper B...atleast 50% i tink..the other quesions are ok i guess....dnt knw..fingers crossed.. :)

[VINEET]

I wish cut off goes down, did some silly mistakes

[VINEET]

and yes nia, I don't know why are they so fond of nia,

[Anjali]

How did you people approach that dx/dt =x^2-x ques ?
How do we judge binding ?

[VINEET]

I chose increasing with no bounds when x was negative. beacause dx/dt is positive. what was the third question of this

[kangkan]

i solved it as a differential equation and solved x explicitly fot t

[VINEET]

so what did you get. and what was the third question of it

[Anjali]

But how do we decide bounds in such ques ? I didn't attempt the. This paper was really scary. Everything unexpected was there .

[kangkan]

hey..lets not discuss answers here..whats done is done

[Anjali]

[Arushi]

How many questions did u people attempt approx? I think I left out quite a few- esp the NIA ones :(

[Granpa Simpson]

wat was the question for the bound one..??

[kangkan]

hey..the question paper had 65 questions right?..mine was option b and had 65 questions

[Anjali]

Yes 65 ques were there
What was the ans for that Sachin Tendulkar ques ?

[Arushi]

Yeah there were 65 questions. Even I had question paper code b. I think all a,b,c should have the same no of questions, just that they're numbered differently.

Sent from my Windows Phone

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From: [hidden email]
Sent: ‎16-‎05-‎2014 09:17 PM
To: [hidden email]
Subject: Re: All the best to all the JNU SSS aspirants...!!!!

hey..the question paper had 65 questions right?..mine was option b and had 65 questions

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NAML

[bhavya jain]

it was (1/2)^5

[CHANGEZ]

bound qn's i solved it like this: (discussion and criticism would be appreciated)
dx/dt=x^2-x; give t was time and shall always be positive.. lets integrate it w.r.t. t
x=(x^2-x)t

Q1: initial value negative; lessay @ t=1s x=-ve and less than -1, then x^2-x will be positive and t is positive therefore increase w/o bound w/ increase in t. +ve X +ve
Q2: initial value positive but (0,1); x^2-x will be negative; w/ increase in t value in negative will increase. therefore decrease w/o bound
Q3: similiarly