ISI INTERVIEW PREP

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Re: ISI INTERVIEW PREP

deepak
Neha, If the determinant is 0,
x^2 - (k-3)x  + k = 0
For x to be real and to have more than 1 distinct value, the discriminant is strictly positive
ie, (k-3)^2 - 4k > 0
or k^2 - 10k + 9 > 0
or (k-9)(k-1) > 0
This would mean the least positive value of k is 1, right?
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Re: ISI INTERVIEW PREP

anon_econ
i did it the same way but then shouldn't it be 9?
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Re: ISI INTERVIEW PREP

anon_econ
oh no it should be 10. neha is right.
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Re: ISI INTERVIEW PREP

anon_econ
In reply to this post by deepak
deepak it can't be 1 bcoz b/w 1 and 9 the discriminant will be negative
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Re: ISI INTERVIEW PREP

deepak
In reply to this post by anon_econ
I'm not sure I understand how 10? Could you explain, please?

ALso, i picked 1 and not 9 because the 'least positive integral value' of k is sought.
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Re: ISI INTERVIEW PREP

deepak
In reply to this post by anon_econ
Extremely silly of me! Thanks :)
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Re: ISI INTERVIEW PREP

Mr. Nobody
In reply to this post by deepak
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Re: ISI INTERVIEW PREP

anurag
In reply to this post by anon_econ
Pardon , @Ram and @vasudha : how did you solve for LTC? :/ (Q.7 part (i))
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Re: ISI INTERVIEW PREP

anon_econ
u find the value of k that minimizes short run total cost. so put dC/dk=0. get k. substitute in the total cost function.
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Re: ISI INTERVIEW PREP

anon_econ
In reply to this post by Mr. Nobody
can u plz explain again how u r getting the equilibrium value of y?
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Re: ISI INTERVIEW PREP

anurag
In reply to this post by anon_econ
thnx :)
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Re: ISI INTERVIEW PREP

neha
For question no. 9, REI of the same paper,, can somebody confirm the following answers?

part (a),, i am getting a =(-1+sqrt of 5)/2 or a=(-1-sqrt of 5)/2 and the function is differentiation at x=0 for both the values of a.

part (b) maximum value of x1x2 =8.

Thanks
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Re: ISI INTERVIEW PREP

anurag
ya even m getting the same answers
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Re: ISI INTERVIEW PREP

anurag
In reply to this post by neha
wt do u think will be d answer in case of minx1x2 ? -8?
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Re: ISI INTERVIEW PREP

neha
@anurag: I think yes. It will be -8 ,, function is not differentiable at x=0 ,, i forgot to write "not" so is that what u are getting?
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Re: ISI INTERVIEW PREP

anurag
ya sry jst checked it again ,no its nt differentiable at 0..
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Re: ISI INTERVIEW PREP

Mr. Nobody
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Re: ISI INTERVIEW PREP

deepak
In reply to this post by Mr. Nobody
Yes I did get a/(a+b) for labor supplied. I don't know 'why' in the economic sense :/ . Mathematically, I think it could perhaps be because the nature of the 'budget constraint' is such that, irrespective of the wage, the Leisure intercept is a constant, and hence, the tangency between the utility indifference curves and the budget lines always occurs at the same value of labor supply (or leisure preference) but consumption is shifted up or down depending on the value of wage. Perhaps because the S.E and I.E are equal and cancel each other out?
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Re: ISI INTERVIEW PREP

Preet
In reply to this post by anurag
Hi Folks,

Look at Q6(b) of JRF 2012 and provide an answer.
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Re: ISI INTERVIEW PREP

neha
In reply to this post by Mr. Nobody
With ref to question 8 part (b), i am getting Y= A*Theta*[a+(a+b)]^Theta + Investment.

The way the i have done is i have found out labor demand function by equating MPL =real wage,, and hence found out w =A*Theta*[a+(a+b)]^(1-Theta).. Since labor supply is fixed, equilibrium labor quantity will be        a+(a+b) so C= A*Theta*[a+(a+b)]^Theta, ergo Y= A*Theta*[a+(a+b)]^Theta + Investment. Any thoughts around it?
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