jnu 2014 discussion

[abhishek23]

@siddharth 19th should be (a) & 21st should be (c)

[urvashi]

how to solve for 52-54?

[maecon]

I don't think the answer for 53 is c , how come x will decrease between 0 and 1 and still reach 1. ?

i guess it should reach 0.

[Kajol]

How to solve Q29?

On May 15, 2016 11:23 AM, "maecon [via Discussion forum]" <[hidden email]> wrote:

I don't think the answer for 53 is c , how come x will decrease between 0 and 1 and still reach 1. ?

i guess it should reach 0.

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[nishtha92]

Sir can you please explain Q 52-54?

[Amit Goyal]

52. When x < 0, dx/dt > 0 --> x will increase over time and when x reaches 0, then dx/dt becomes 0, so the value of x stays at 0 after that. So, the answer is (b) Increases and approach 0 overtime.

53. When 0<x<1, dx/dt < 0 --> x will decrease over time and when x reach 0, then dx/dt = 0, so the value of x stays at 0 after that. So, the answer is Decreases and approach 0 overtime, therefore, none of the options is correct.

54. When x > 1, dx/dt > 0 --> x will increase over time without any bound. So, the answer is (d).

[nishtha92]

Thank you so much sir.

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From: [hidden email]
Sent: ‎15-‎05-‎2016 21:28
To: [hidden email]
Subject: Re: jnu 2014 discussion

52. When x < 0, dx/dt > 0 --> x will increase over time and when x reaches 0, then dx/dt becomes 0, so the value of x stays at 0 after that. So, the answer is (b) Increases and approach 0 overtime.

53. When 0<x<1, dx/dt < 0 --> x will decrease over time and when x reach 0, then dx/dt = 0, so the value of x stays at 0 after that. So, the answer is Decreases and approach 0 overtime, therefore, none of the options is correct.

54. When x > 1, dx/dt > 0 --> x will increase over time without any bound. So, the answer is (d).

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